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(2)=3F^2+7
We move all terms to the left:
(2)-(3F^2+7)=0
We get rid of parentheses
-3F^2-7+2=0
We add all the numbers together, and all the variables
-3F^2-5=0
a = -3; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·(-3)·(-5)
Δ = -60
Delta is less than zero, so there is no solution for the equation
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